Most C++ quirks can be argued by efficency or inheritence reasons. But sometimes I just don't see why there is yet another exception in the rules of the language. Such an example is the initialization of static constant data members:
Section 9.4.4 of the ISO standard says:
If a static data member is of const integral or const enumeration type, its declaration in the class definition can specify a constant-initializer which shall be an integral constant expression.
Here is an example of this:
class X {
static const int i = 23;
};
Now, I wonder why this in-place initialization is restricted to those two types. I would like to be a able to express:
class A;
class X {
public:
static const A* special_meaning=0;
void do_something(const A* with=special_meaning);
};
C++ prevents me from writing descriptive code in this case. And for
what reason? I can't see any.
By the way, section 9.4.4 adds:
The member shall still be defined in a namespace scope if it is used in the program and the namespace scope definition shall not contain an initializer.Sure, linker and such... So what is this in-place initialization good for after all?
Thank you, Liesa
What's the value of X::i?
int g() { return 23;}
struct X {
static int g() { return 42; }
static int i;
};
int X::i = g();
The answer is: 42 - says ISO C++ in section 9.4.2. The initialization of the static data member is implicit in the scope of the struct. Oh, yes! The standard's example is even more fun:
int g();
struct X {
static int g();
};
struct Y : X {
static int i;
};
int Y::i = g(); // equivalent to Y::g();
Note that X could be definied in another header file
than g and that the initialization normaly is in a
cc-file. Find, Rover, find!
Thank you, Roker